web sites
Measurements
Download
http://plasma4.sr.unh.edu/ng/phys407/phys407-6-13-05.pdf
--------------------------
JEE 2007 Paper I
--------------------------------------------.
Q.I. Some physical quantities are given in column I and some possible SI units in which these
quantities may be expressed are given in column II. Match the physical quantities in column I
with the units in Column II and indicate your answer by darkening appropriate bubbles in the 4 ×
4 matrix given in the ORS.
Column I
==================================================
A.
GM-e M-s ------ ---[ P. (volt) (coulomb) (metre)]
G – universal gravitational constant,
M-e – mass of the earth
M-s – Mass of the Sun
==================================================
B.
3RT/M --------------[Q. (kilogram)(metre^3)(second^-2)]
R – universal gas constant
T – absolute temperature
M – molar mass
==================================================
C.
F^2/(B^2Q^2)------------------------------[R. (metre^2)(second^-2)]
F – force
Q – charge
B – magnetic field
=================================================
D
(GM-e)/R-e ------------[S. (farad)(volt^2)(kg^-1)]
G – universal gravitational constant,
M-e – mass of the earth
R-e – radius of the earth
=================================================
Answer
(A) -- (P), (Q)
(B) -- (R), (S)
(C) -- (R) , S
(D) -- R, S
----------------------------------------------------------------
Q.II. Column I gives certain situations in which a straight metallic wire of resistance R is used and column II gives some resulting effects. Match the statement in column I with the statements in column II and indicate your answer by darkening appropriate bubbles in the 4 × 4 matrix given in the ORS.
================================
Column I -----------------------------Column II
(A to D) -----------------------------(P to S)
==========================================================
(A) A charged capacitor is ---(P) A constant current flows
connected to------------------through the wire
the ends of the wire
===========================================================
(B)The wire is moved ----------(Q) thermal energy
perpendicular to its length -------generated in the wire
length with a constant
velocity in a uniform magnetic field
perpendicular to the plane of motion
===========================================================
(C)
The wire is placed in a -----------(R) A constant potential
constant electric field ---------- difference develops
that has direction-----------------between the ends of
along the length of the wire-------the wire
============================================================
(D) A battery of constant ----------(S) Charges of constant
emf is connected to the --------------- magnitude appear
ends of the wire-----------------------at the ends of the wire
============================================================
Solution
(A) -- (Q)
(B) -- (R), (S),
(C) -- (S)
(D) -- (P), (Q) , (R)
-----------------------------------------------------
Q. III.
Some laws/ processes are given in Column I. Match these with physical phenomena given in Column II and indicate your answer by darkening appropriate bubbles in the 4 × 4 matrix given in the ORS.
---Column I ------------------------Column II
A. Transition between -----------P.Characteristic X-rays
two atomic energy----------------
levles
B. Electron emission-------------Q. Photoelectric effect
from a material------------------
C. Mosley’s law------------------R. Hydrogen spectrum
D. Change of photon--------------S. β – decay
energy into kinetic--------------
energy of electrons--------------
===================
Solution
(A) -- (P), (R)
(B) ® (Q), (S),
(C) ® (P)
(D) ® (Q)
-----------------------------------
Q.4 JEE 2007 paper II
Column I gives some devices and Column II gives some processes on which the functioning of these devices depend. Match the devices in Column I with the processes in Column II and indicate your answer by darkening appropriate bubbles
in the 4 × 4 matrix given in the ORS.
--------Column I--------------Column II
(A) Bimetallic strip-----(P)Radiation from a hot body
(B) Steam engine-------- (Q)Energy conversion
(C) Incandescent lamp----(R) Melting
(D) Electric fuse--------(S) Thermal expansion of solids
Solution:
(A) – (S)
(B) – (Q)
(C) – (P), (Q)
(D) – (R), (Q)
(A) Bimetallic strip works on the principle of thermal expansion of solids.
(B) Steam engine converts steam energy into mechanical energy.
(C) Incandescent lamp works on the principle of radiation of body due to temperature.
(D) Electric fuse is a safety device which does not allow current more than its permissible value.
----------------------------
Q5. JEE 2007 Paper II
Column I describes some situations in which a small object moves. Column II describes some characteristics of these motions. Match the situations in Column I with the characteristics in Column II and indicate your answer by darkening
appropriate bubbles in the 4 × 4 matrix given in the ORS.
Column I is give first totally. and then Column II is given next.
A. The object moves on the x-axis under a conservative force in
such a way that its “speed” and “position” satisfy
v =c1*SQRT(c2-x^2), where c1 and c2 are positive constants.
B. The object moves on the x-axis in such a way that its velocity
and its displacement from the origin satisfy kx v − = , where k
is a positive constant.
C. The object is attached to one end of a mass less spring of a
given spring constant. The other end of the spring is attached
to the ceiling on an elevator. Initially everything is at rest. The
elevator starts going upwards with a constant acceleration a.
The motion of the object is observed from the elevator during
the period it maintains this acceleration.
D.The object is projected from the earth’s surface vertically
upwards with a speed SQRT(GM-e/R-e) , where, M-e is the mass
of the earth and R-e is the radius of the earth. Neglect forces
from objects other than the earth.
Column II
(P) The object executes a simple harmonic
motion.
(Q) The object does not change its direction
(R) The kinetic energy of the object keeps on
decreasing
(S) The object can change its direction only once.
Solution:
(A) – (P)
(B) – (Q), (R)
(C) – (P)
(D) – (Q), (R)
--------------------------------------------
COMPANION SITES: www.iit-jee-chemistry.blogspot.com, www.iit-jee-maths.blogspot.com. A google search facility is available at the bottom of the page for searching any topic on these sites.
Wednesday, October 24, 2007
Tuesday, October 23, 2007
Study guide H C Verma JEE Physics Ch. 1 INTRODUCTION TO PHYSICS
H C Verma Book Sections
1.1 What is Physics
1.2 Physics and Mathematics
1.3 Units
1.4 Definitions of base units
1.5 Dimension
1.6 Uses of dimension
1.7 Order of magnitude
1.8 The structure of world
Study Plan
Study plan basically consists of 10 days of study and problems solving. Additional 10 days is for revision and for solving some more problems from the book, if you could not complete them during the first 10 days. Each day spend at least one hour for this subject for the main chapter and may be 15 minutes to 30 minutes for revising the earlier chapter. Thus you have to allot at least three hours and forty five minutes every day for your self study. It will be good when you are able to combine your self study with the lecture that is going in the school and coaching class. That way you will be able to complete self study in lesser time and get the benefit of reinforcement.
Day 1
Study
1.1 What is Physics
1.2 Physics and Mathematics
1.3 Units
1.4 Definitions of base units
1.5 Dimension
Do example 1.1
Do worked out examples 1 and 2
Day 2
Study
1.6 Uses of dimension
Do example 1.2
Do worked out examples 3,4,5,6
Day 3
Study
1.7 Order of magnitude
1.8 The structure of world
Do worked out examples 7 to 10
Day 4
Revise the chapter
Answer Objective I and II
Day 5
Solve Exercises 1 to 5
Day 6
Solve Exercises 6 to 10
Day 7
Solve Exercises 11 to 15
Day 8
Solve Exercises 16 to 19
Day 9 to 20
Keep revising principles, and have a look at difficult problems. If you come across any other text book, answer problems in that textbook on these topics.
By the end of these 20 days, you must be very thorough with this chapter. You are ready to write examination on this chapter at any time from today.
1.1 What is Physics
1.2 Physics and Mathematics
1.3 Units
1.4 Definitions of base units
1.5 Dimension
1.6 Uses of dimension
1.7 Order of magnitude
1.8 The structure of world
Study Plan
Study plan basically consists of 10 days of study and problems solving. Additional 10 days is for revision and for solving some more problems from the book, if you could not complete them during the first 10 days. Each day spend at least one hour for this subject for the main chapter and may be 15 minutes to 30 minutes for revising the earlier chapter. Thus you have to allot at least three hours and forty five minutes every day for your self study. It will be good when you are able to combine your self study with the lecture that is going in the school and coaching class. That way you will be able to complete self study in lesser time and get the benefit of reinforcement.
Day 1
Study
1.1 What is Physics
1.2 Physics and Mathematics
1.3 Units
1.4 Definitions of base units
1.5 Dimension
Do example 1.1
Do worked out examples 1 and 2
Day 2
Study
1.6 Uses of dimension
Do example 1.2
Do worked out examples 3,4,5,6
Day 3
Study
1.7 Order of magnitude
1.8 The structure of world
Do worked out examples 7 to 10
Day 4
Revise the chapter
Answer Objective I and II
Day 5
Solve Exercises 1 to 5
Day 6
Solve Exercises 6 to 10
Day 7
Solve Exercises 11 to 15
Day 8
Solve Exercises 16 to 19
Day 9 to 20
Keep revising principles, and have a look at difficult problems. If you come across any other text book, answer problems in that textbook on these topics.
By the end of these 20 days, you must be very thorough with this chapter. You are ready to write examination on this chapter at any time from today.
Study guide H C Verma JEE Physics Ch. 2 PHYSICS AND MATHEMATICS
HCV Chapter Sections
2.1 Vectors and scalars
2.2 Equality of vectors
2.3 Addition of vectors
2.4 Multiplication of a vector by a number
2.5 Subtraction of vectors
2.6 Resolution of vectors
2.7 DCT product or scalar product of two vectors
2.8 Cross product or vector product of two vectors
2.9 Differential calculus: dy/dx as rate measure
2.10 Maxima and Minima
2.11 Integral calculus
2.12 Significant digits
2.13 Significant digits in calculations
2.14 Errors in measurements
Study Plan
Day 1
2.1 Vectors and scalars
2.2 Equality of vectors
2.3 Addition of vectors
Example 2.1
2.4 Multiplication of a vector by a number
2.5 Subtraction of vectors
Example 2.2
Day 2
2.6 Resolution of vectors
Example 2.3
2.7 DOT product or scalar product of two vectors
Example 2.4
Worked out examples 1 to 4
Day 3
2.8 Cross product or vector product of two vectors
Example 2.5
Worked out example 5 to 10.
Day 4
2.9 Differential calculus: dy/dx as rate measure
Ex. 2.6, 2.7
2.10 Maxima and Minima
Ex.2.8
Day 5
2.11 Integral calculus
Ex. 2.9
Worked out examples 11 to 13
Day 6
2.12 Significant digits
2.13 Significant digits in calculations
Ex. 2.10 to 2.12
Worked out examples 14 to 17
Day 7
2.14 Errors in measurements
Ex. 2.13
Worked example 18
Exercise Problems: 1 to 4
Day 8
Objective I
Exercise Problems 5 to 8
Day 9
Objective II
Exercise Problems 9 to 12
Day 10
Exercise Problems 13 to 20
Day 11 Your are entering into revision 10 days
Exercise problems 21,22
Day 12
Exercise problems 23,24
Day 13
Exercise problems 25,26
Day 14
Exercise problems 27,28
Day 15
Exercise problems 29,30
Day 16
Exercise problems 31,32
Day 17
Exercise problems 33,34
Day 18
Exercise problems 35
Day 19
Attempt Questions for short answer 1 to 7
Day 20
Exercise problems
Attempt Questions for short answer 8 to 14
Web sites
lecture notes - Vectors
http://plasma4.sr.unh.edu/ng/phys407/phys407-6-16-05.pdf
2.1 Vectors and scalars
2.2 Equality of vectors
2.3 Addition of vectors
2.4 Multiplication of a vector by a number
2.5 Subtraction of vectors
2.6 Resolution of vectors
2.7 DCT product or scalar product of two vectors
2.8 Cross product or vector product of two vectors
2.9 Differential calculus: dy/dx as rate measure
2.10 Maxima and Minima
2.11 Integral calculus
2.12 Significant digits
2.13 Significant digits in calculations
2.14 Errors in measurements
Study Plan
Day 1
2.1 Vectors and scalars
2.2 Equality of vectors
2.3 Addition of vectors
Example 2.1
2.4 Multiplication of a vector by a number
2.5 Subtraction of vectors
Example 2.2
Day 2
2.6 Resolution of vectors
Example 2.3
2.7 DOT product or scalar product of two vectors
Example 2.4
Worked out examples 1 to 4
Day 3
2.8 Cross product or vector product of two vectors
Example 2.5
Worked out example 5 to 10.
Day 4
2.9 Differential calculus: dy/dx as rate measure
Ex. 2.6, 2.7
2.10 Maxima and Minima
Ex.2.8
Day 5
2.11 Integral calculus
Ex. 2.9
Worked out examples 11 to 13
Day 6
2.12 Significant digits
2.13 Significant digits in calculations
Ex. 2.10 to 2.12
Worked out examples 14 to 17
Day 7
2.14 Errors in measurements
Ex. 2.13
Worked example 18
Exercise Problems: 1 to 4
Day 8
Objective I
Exercise Problems 5 to 8
Day 9
Objective II
Exercise Problems 9 to 12
Day 10
Exercise Problems 13 to 20
Day 11 Your are entering into revision 10 days
Exercise problems 21,22
Day 12
Exercise problems 23,24
Day 13
Exercise problems 25,26
Day 14
Exercise problems 27,28
Day 15
Exercise problems 29,30
Day 16
Exercise problems 31,32
Day 17
Exercise problems 33,34
Day 18
Exercise problems 35
Day 19
Attempt Questions for short answer 1 to 7
Day 20
Exercise problems
Attempt Questions for short answer 8 to 14
Web sites
lecture notes - Vectors
http://plasma4.sr.unh.edu/ng/phys407/phys407-6-16-05.pdf
Study guide H C Verma JEE Physics Ch. 3 REST AND MOTION - KINEMATICS
Inertial and uniformly accelerated frames of reference;
-----------
HCV Chapter Sections
3.1 Rest and Motion
3.2 Distance and displacement
3.3 average speed and instantaneous speed
3.4 Average velocity and instantaneous velocity
3.5 Average accleration and instantaneous aceleration
3.6 Motion in a straight line
3.7 Motion in a plane
3.8 Projectile motion
3.9 Change of frame
-------
Study Plan
Day 1
3.1 Rest and Motion
3.2 Distance and displacement
Ex. 3.1
3.3 average speed and instantaneous speed
Ex. 3.2,3.3
Worked out example 1
Points to Note in the session
http://iit-jee-physics.blogspot.com/2009/05/physics-study-diary-for-iit-jee-2011.html
Day 2
4. Average velocity and instantaneous velocity
Ex. 3.4
Worked out example 2
3.5 Average accleration and instantaneous aceleration
Exercises: 1 to 5
Points to Note in the session
http://iit-jee-physics.blogspot.com/2009/05/physics-study-diary-for-iit-jee-ch3.html
Day 3
3.6 Motion in a straight line
Ex. 3.5.3.6, 3.7
WOE 3 to 6
Points to Note in the session
http://iit-jee-physics.blogspot.com/2009/05/iit-jee-physics-study-diary-ch3-rest.html
Day 4
3.7 Motion in a plane
Ex. 3.8
3.8 Projectile motion
Ex. 3.9
WOE 11,12, 14
Day 5
3.9 Change of frame
Ex. 3.10, 3.11
WOE 16,17, 18
Day 6
Formula Revision
http://iit-jee-physics.blogspot.com/2008/02/iit-jee-physics-formula-revision-3-rest.html
WOE 7 to 10, and 13,15, 19,20
Day 7
Exercises 6 to 15
Day 8
Exercises 16 to 25
Day 9
Exercises 26 to 35
Day 10
Exercises 36 to 45
Revision Period
Day 11
Exercises 46 to 50
Day 12
Exercises 51,52
Objective I
Day 13
Exercises
Objective II
Day 14
Exercises
Question for short answer
Day 15
Concept review
http://iit-jee-physics.blogspot.com/2008/05/concept-review-chapter-3-rest-and.html
Day 16
Formula review
http://iit-jee-physics.blogspot.com/2008/02/iit-jee-physics-formula-revision-3-rest.html
Day 17 to 20
Test paper problems 10 per day can be solved.
Inertial and accelerated frames of reference.
Section 3.9 covers material related to it. But it is not using the terms inertial frame of reference.
------
Past JEE question
1982
A particle is moving eastwards with a velocity 5 m/s. In 10 seconds the velocity changes to 5 m/s northwards. The average acceleration in this time is
a) zero
b) [1/Sqrt(2)]m/s^2 towards northwest
c) 1/2 m/s^2 towards northwest
d) 1/2 m/s^2 towards north
Answer b.
You can find acceleration in the direction of west and check that velocity become zero in east direction in 5 seconds and also velocity in north direction becomes 5 m/s.
----------------------
Audio visual lectures
http://www.curriki.org/nroc/Introductory_Physics_1/lesson01/Container.html
Motion in two dimensions (plane)
http://www.curriki.org/nroc/Introductory_Physics_1/lesson02/Container.html
web sites
one dimensional motion
http://plasma4.sr.unh.edu/ng/phys407/phys407-6-15-05.pdf
-----------
HCV Chapter Sections
3.1 Rest and Motion
3.2 Distance and displacement
3.3 average speed and instantaneous speed
3.4 Average velocity and instantaneous velocity
3.5 Average accleration and instantaneous aceleration
3.6 Motion in a straight line
3.7 Motion in a plane
3.8 Projectile motion
3.9 Change of frame
-------
Study Plan
Day 1
3.1 Rest and Motion
3.2 Distance and displacement
Ex. 3.1
3.3 average speed and instantaneous speed
Ex. 3.2,3.3
Worked out example 1
Points to Note in the session
http://iit-jee-physics.blogspot.com/2009/05/physics-study-diary-for-iit-jee-2011.html
Day 2
4. Average velocity and instantaneous velocity
Ex. 3.4
Worked out example 2
3.5 Average accleration and instantaneous aceleration
Exercises: 1 to 5
Points to Note in the session
http://iit-jee-physics.blogspot.com/2009/05/physics-study-diary-for-iit-jee-ch3.html
Day 3
3.6 Motion in a straight line
Ex. 3.5.3.6, 3.7
WOE 3 to 6
Points to Note in the session
http://iit-jee-physics.blogspot.com/2009/05/iit-jee-physics-study-diary-ch3-rest.html
Day 4
3.7 Motion in a plane
Ex. 3.8
3.8 Projectile motion
Ex. 3.9
WOE 11,12, 14
Day 5
3.9 Change of frame
Ex. 3.10, 3.11
WOE 16,17, 18
Day 6
Formula Revision
http://iit-jee-physics.blogspot.com/2008/02/iit-jee-physics-formula-revision-3-rest.html
WOE 7 to 10, and 13,15, 19,20
Day 7
Exercises 6 to 15
Day 8
Exercises 16 to 25
Day 9
Exercises 26 to 35
Day 10
Exercises 36 to 45
Revision Period
Day 11
Exercises 46 to 50
Day 12
Exercises 51,52
Objective I
Day 13
Exercises
Objective II
Day 14
Exercises
Question for short answer
Day 15
Concept review
http://iit-jee-physics.blogspot.com/2008/05/concept-review-chapter-3-rest-and.html
Day 16
Formula review
http://iit-jee-physics.blogspot.com/2008/02/iit-jee-physics-formula-revision-3-rest.html
Day 17 to 20
Test paper problems 10 per day can be solved.
Inertial and accelerated frames of reference.
Section 3.9 covers material related to it. But it is not using the terms inertial frame of reference.
------
Past JEE question
1982
A particle is moving eastwards with a velocity 5 m/s. In 10 seconds the velocity changes to 5 m/s northwards. The average acceleration in this time is
a) zero
b) [1/Sqrt(2)]m/s^2 towards northwest
c) 1/2 m/s^2 towards northwest
d) 1/2 m/s^2 towards north
Answer b.
You can find acceleration in the direction of west and check that velocity become zero in east direction in 5 seconds and also velocity in north direction becomes 5 m/s.
----------------------
Audio visual lectures
http://www.curriki.org/nroc/Introductory_Physics_1/lesson01/Container.html
Motion in two dimensions (plane)
http://www.curriki.org/nroc/Introductory_Physics_1/lesson02/Container.html
web sites
one dimensional motion
http://plasma4.sr.unh.edu/ng/phys407/phys407-6-15-05.pdf
Study guide H C Verma JEE Physics Ch. 5 NEWTON'S LAWS OF MOTION
Newton’s laws of motion;
--------------
Main Sections
5.1 Newton's First law
5.2 Newton's second law
5.3 Working with Newton's laws
5.4 Newton's third law of motion
5.5 Pseudo forces
5.6 The Horse and the cart
5.7 Inertia
---------------------
Subsections under each main section
5.1 First law of motion
Inertial frames other than earth
5.2 Newton's second law
5.3 Working with Newton's laws
5.4 Newton's third law of motion
5.5 Pseudo forces
5.6 The Horse and the cart
5.7 Inertia
------------
Study Plan
Day 1
5.1 First law of motion
Example 5.1
W.O.E. 1 and 2
http://iit-jee-physics.blogspot.com/2008/08/newtons-laws-of-motion-study-plan.html
Day 2
5.2 Newton's second law
5.3 Working with Newton's laws
W.O.E. 3 and 4
Points to be noted
http://iit-jee-physics.blogspot.com/2008/09/newtons-laws-of-motion-study-plan.html
Day 3
5.4 Newton's third law of motion
W.O.E. 5,6
Day 4
5.5 Pseudo forces
W.O.E. 7,8
Day 5
5.6 The Horse and the cart
5.7 Inertia
W.O.E. 9,10,11
Day 6
Chapter 5
Objective I
Day 7
Chapter 5
Objective II
Day 8
Chapter 5
Exercises 1 to 5
Day 9
Chapter 5
Exercises 6 to 10
Day 10
Chapter 5
Exercises 11 to 15
Day 11
Chapter 5 Revision
Exercises 16 to 18
Day 12
Chapter 5 Revision
Exercises 19 to 21
Day 13
Chapter 5 Revision
Exercises 22 to 24
Day 14
Chapter 5 Revision
Exercises 25 to 27
Day 15
Chapter 5 Revision
Exercises 28 to 30
Day 16
Chapter 5 Revision
Exercises 31 to 33
Day 17
Chapter 5 Revision
Exercises 34 to 36
Day 18
Chapter 5 Revision
Exercises 37 to 39
Day 19
Chapter 5 Revision
Exercises 40 to 42
Day 20
Chapter 5 Revision
Attempt Questions for short Answer 1 to 17
Audiovisual lecture
Newton's first law
http://www.curriki.org/nroc/Introductory_Physics_1/lesson03/Container.html
Newton's second law
http://www.curriki.org/nroc/Introductory_Physics_1/lesson04/Container.html
Newton's thrid law
http://www.curriki.org/nroc/Introductory_Physics_1/lesson05/Container.html
Newton's laws - applications
http://www.curriki.org/nroc/Introductory_Physics_1/lesson06/Container.html
Websites
plasma4.sr.unh.edu/ng/phys407/phys407-6-23-05.pdf
-----------------
JEE Question 2007 Paper II
Statement - 1
A cloth covers a table. Some dishes are kept on it. The cloth can be pulled out without dislodging the dishes from the table.
Because
Statement - 2
For every action there is an equal an opposite reaction.
(A) Statement – 1 is True, Statement – 2 is True; Statement – 2 is a correct explanation for statement – 1
(B) Statement – 1 is True, Statement – 2 is True; Statement – 2 is Not a correct explanation for Statement – 1.
(C) Statement – 1 is True, Statement – 2 is False
(D) Statement – 1 is False, Statement – 2 is True
Correct choice: (B)
S1 is correct.
S2 is also correct but it does not explain S1. S1 is possible because of inertia.
-----------------------
---------
JEE Question 2007 Paper I
Two particles of mass m each are tied at the ends of a light string of
length 2a. The whole system is kept on a frictionless horizontal surface
with the string held tight so that each mass is at a distance ‘a’ from the
centre P (as shown in the figure. *figure not given in this post). Now, the mid-point of the string is pulled vertically upwards with a small but constant force F. As a result,the particles move towards each other on the surface. The magnitude of
acceleration, when the separation between them becomes 2x, is
(A) (F/2m)(a/SQRT(a^2-x^2))
(B) (F/2m)(x/SQRT(a^2-x^2))
(C) (F/2m)(x/a)
(D) (F/2m)(SQRT(a^2-x^2)/x)
Solution: B
Imagine the string being pulled upward from midpoint, but only horizontal movement is there.Assume that the string makes with the horizontal surface is θ (theta) , and the tension in the string is T.
F = 2Tsinθ (Tension in each side of the string)
Force in the horintal direction on each particle = F' = ma = T Cosθ
So a = T Cosθ/m
T = F/2Sinθ
a = (F/2m)cotθ
In the triange formed between half of the string and horizontal surface,and the imaginary vertical line through which force is being applied, diagonal is half of the string hence a, and the horizontal side is x. The third side is SQRT(a^2-x^2)
Hence cotθ = x/SQRT(a^2-x^2)
a = (F/2m)(x/SQRT(a^2-x^2))
---------------------
--------------
Main Sections
5.1 Newton's First law
5.2 Newton's second law
5.3 Working with Newton's laws
5.4 Newton's third law of motion
5.5 Pseudo forces
5.6 The Horse and the cart
5.7 Inertia
---------------------
Subsections under each main section
5.1 First law of motion
Inertial frames other than earth
5.2 Newton's second law
5.3 Working with Newton's laws
5.4 Newton's third law of motion
5.5 Pseudo forces
5.6 The Horse and the cart
5.7 Inertia
------------
Study Plan
Day 1
5.1 First law of motion
Example 5.1
W.O.E. 1 and 2
http://iit-jee-physics.blogspot.com/2008/08/newtons-laws-of-motion-study-plan.html
Day 2
5.2 Newton's second law
5.3 Working with Newton's laws
W.O.E. 3 and 4
Points to be noted
http://iit-jee-physics.blogspot.com/2008/09/newtons-laws-of-motion-study-plan.html
Day 3
5.4 Newton's third law of motion
W.O.E. 5,6
Day 4
5.5 Pseudo forces
W.O.E. 7,8
Day 5
5.6 The Horse and the cart
5.7 Inertia
W.O.E. 9,10,11
Day 6
Chapter 5
Objective I
Day 7
Chapter 5
Objective II
Day 8
Chapter 5
Exercises 1 to 5
Day 9
Chapter 5
Exercises 6 to 10
Day 10
Chapter 5
Exercises 11 to 15
Day 11
Chapter 5 Revision
Exercises 16 to 18
Day 12
Chapter 5 Revision
Exercises 19 to 21
Day 13
Chapter 5 Revision
Exercises 22 to 24
Day 14
Chapter 5 Revision
Exercises 25 to 27
Day 15
Chapter 5 Revision
Exercises 28 to 30
Day 16
Chapter 5 Revision
Exercises 31 to 33
Day 17
Chapter 5 Revision
Exercises 34 to 36
Day 18
Chapter 5 Revision
Exercises 37 to 39
Day 19
Chapter 5 Revision
Exercises 40 to 42
Day 20
Chapter 5 Revision
Attempt Questions for short Answer 1 to 17
Audiovisual lecture
Newton's first law
http://www.curriki.org/nroc/Introductory_Physics_1/lesson03/Container.html
Newton's second law
http://www.curriki.org/nroc/Introductory_Physics_1/lesson04/Container.html
Newton's thrid law
http://www.curriki.org/nroc/Introductory_Physics_1/lesson05/Container.html
Newton's laws - applications
http://www.curriki.org/nroc/Introductory_Physics_1/lesson06/Container.html
Websites
plasma4.sr.unh.edu/ng/phys407/phys407-6-23-05.pdf
-----------------
JEE Question 2007 Paper II
Statement - 1
A cloth covers a table. Some dishes are kept on it. The cloth can be pulled out without dislodging the dishes from the table.
Because
Statement - 2
For every action there is an equal an opposite reaction.
(A) Statement – 1 is True, Statement – 2 is True; Statement – 2 is a correct explanation for statement – 1
(B) Statement – 1 is True, Statement – 2 is True; Statement – 2 is Not a correct explanation for Statement – 1.
(C) Statement – 1 is True, Statement – 2 is False
(D) Statement – 1 is False, Statement – 2 is True
Correct choice: (B)
S1 is correct.
S2 is also correct but it does not explain S1. S1 is possible because of inertia.
-----------------------
---------
JEE Question 2007 Paper I
Two particles of mass m each are tied at the ends of a light string of
length 2a. The whole system is kept on a frictionless horizontal surface
with the string held tight so that each mass is at a distance ‘a’ from the
centre P (as shown in the figure. *figure not given in this post). Now, the mid-point of the string is pulled vertically upwards with a small but constant force F. As a result,the particles move towards each other on the surface. The magnitude of
acceleration, when the separation between them becomes 2x, is
(A) (F/2m)(a/SQRT(a^2-x^2))
(B) (F/2m)(x/SQRT(a^2-x^2))
(C) (F/2m)(x/a)
(D) (F/2m)(SQRT(a^2-x^2)/x)
Solution: B
Imagine the string being pulled upward from midpoint, but only horizontal movement is there.Assume that the string makes with the horizontal surface is θ (theta) , and the tension in the string is T.
F = 2Tsinθ (Tension in each side of the string)
Force in the horintal direction on each particle = F' = ma = T Cosθ
So a = T Cosθ/m
T = F/2Sinθ
a = (F/2m)cotθ
In the triange formed between half of the string and horizontal surface,and the imaginary vertical line through which force is being applied, diagonal is half of the string hence a, and the horizontal side is x. The third side is SQRT(a^2-x^2)
Hence cotθ = x/SQRT(a^2-x^2)
a = (F/2m)(x/SQRT(a^2-x^2))
---------------------
Study guide H C Verma JEE Physics Ch. 6 FRICTION
JEE Syllabus
Static and dynamic friction;
----
Sections of the chapter
6.1 Friction as the component of contact force
6.2 Kinetic friction
6.3 Static friction
6.4 Laws of friction
6.5 Understandng friction at atomic level
6.6 A Laboratory method to measure friction coefficient
--------
Study Plan
Day 1
6.1 Friction as the component of contact force
Example 6.1
6.2 Kinetic friction
Example 6.2
Day 2
6.3 Static friction
Ex. 6.3
W.O.E. 1,2,3,4
Day 3
6.4 Laws of friction
W.O.E. 5 to 8
Day 4
6.5 Understandng friction at atomic level
6.6 A Laboratory method to measure friction coefficient
Ex. 6.4
W.O.E. 9,10
Day 5
Chapter 6
Objective I
Day 6
Chapter 6
Objective II
Day 7
Chapter 6
Exercises 1 to 5
Day 8
Chapter 6
Exercises 6 to 10
Day 9
Chapter 6
Exercises 11 to 15
Day 10
Chapter 6
Exercises 16 to 20
Revision Period
Day 11
Chapter 6 Revision
Exercises 21 to 23
Day 12
Chapter 6 Revision
Exercises 24 to 27
Day 13
Chapter 6 Revision
Exercises 28 to 30
Day 14
Chapter 6 Revision
Exercises 31,
Day 15
Chapter 6 Revision
Questions for Short Answer: 1 to 11
-----------
web sites
lecture notes
http://plasma4.sr.unh.edu/ng/phys407/phys407-6-27-05.pdf
----------------
JEE question 2007 paper I
STATEMENT-1
A block of mass m starts moving on a rough horizontal surface with a velocity v. It stops due to friction between the block and the surface after moving through a certain distance. The surface is now tilted to an angle of 30 degrees with the horizontal and the same block is made to go up on the surface with the same initial velocity v. The decrease in the mechanical energy in the second situation is smaller than that in the first situation.
because
STATEMENT-2
The coefficient of friction between the block and the surface decreases with the increase in the angle of inclination.
(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1
(C) Statement-1 is True, Statement-2 is False
(D) Statement-1 is False, Statement-2 is True
Correct choice: (C)
Coefficient of friction doesn’t depend on the angle of inclination of the plane.
----------------------------------------
Static and dynamic friction;
----
Sections of the chapter
6.1 Friction as the component of contact force
6.2 Kinetic friction
6.3 Static friction
6.4 Laws of friction
6.5 Understandng friction at atomic level
6.6 A Laboratory method to measure friction coefficient
--------
Study Plan
Day 1
6.1 Friction as the component of contact force
Example 6.1
6.2 Kinetic friction
Example 6.2
Day 2
6.3 Static friction
Ex. 6.3
W.O.E. 1,2,3,4
Day 3
6.4 Laws of friction
W.O.E. 5 to 8
Day 4
6.5 Understandng friction at atomic level
6.6 A Laboratory method to measure friction coefficient
Ex. 6.4
W.O.E. 9,10
Day 5
Chapter 6
Objective I
Day 6
Chapter 6
Objective II
Day 7
Chapter 6
Exercises 1 to 5
Day 8
Chapter 6
Exercises 6 to 10
Day 9
Chapter 6
Exercises 11 to 15
Day 10
Chapter 6
Exercises 16 to 20
Revision Period
Day 11
Chapter 6 Revision
Exercises 21 to 23
Day 12
Chapter 6 Revision
Exercises 24 to 27
Day 13
Chapter 6 Revision
Exercises 28 to 30
Day 14
Chapter 6 Revision
Exercises 31,
Day 15
Chapter 6 Revision
Questions for Short Answer: 1 to 11
-----------
web sites
lecture notes
http://plasma4.sr.unh.edu/ng/phys407/phys407-6-27-05.pdf
----------------
JEE question 2007 paper I
STATEMENT-1
A block of mass m starts moving on a rough horizontal surface with a velocity v. It stops due to friction between the block and the surface after moving through a certain distance. The surface is now tilted to an angle of 30 degrees with the horizontal and the same block is made to go up on the surface with the same initial velocity v. The decrease in the mechanical energy in the second situation is smaller than that in the first situation.
because
STATEMENT-2
The coefficient of friction between the block and the surface decreases with the increase in the angle of inclination.
(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1
(C) Statement-1 is True, Statement-2 is False
(D) Statement-1 is False, Statement-2 is True
Correct choice: (C)
Coefficient of friction doesn’t depend on the angle of inclination of the plane.
----------------------------------------
Study guide H C Verma JEE Physics Ch. 7 CIRCULAR MOTION
JEE Syllabus
Uniform Circular motion;
-----------
Sections of the chapter
7.1 Angular variables
7.2 Unit vectors along the radius and the tangent
7.3 Acceleration in circular motion
7.4 Dynamics of circular motion
7.5 Circular turnings and banking of roads
7.6 Centrifugal force
7.7 Effect of earth's rotation on apprarent weight
------------
Study Plan
Day 1
7.1 Angular variables
Ex. 7.1, 7.2
7.2 Unit vectors along the radius and the tangent
Day 2
7.3 Acceleration in circular motion
Ex. 7.3,7.4
7.4 Dynamics of circular motion
Ex. 7.5
W.O.E. 3,4,5,7
Day 3
7.5 Circular turnings and banking of roads
Ex. 7.6
W.O.E. 1 and 2
Day 4
7.6 Centrifugal force
w.O.E. 7, 8,9,10,
Day 5
7.7 Effect of earth's rotation on apprarent weight
Ex. 7.7
w.O.E. 11 to 13
Day 6
Chapter 7
Objective I
Day 7
Chapter 7
Objective II
Day 8
Chapter 7
Exercises 1 to 5
Day 9
Chapter 7
Exercises 6 to 10
Day 10
Chapter 7
Exercises 11 to 15
Revision period
Chapter 7 Revision
Day 11
Chapter 7 Revision
Exercises: 16 to 18
Day 12
Chapter 7 Revision
Exercises: 19 to 21
Day 13
Chapter 7 Revision
Exercises: 22 to 24
Day 14
Chapter 7 Revision
Exercises: 25 to 27
Day 15
Chapter 7 Revision
Exercises: 28 to 30
Day 16
Chapter 7 Revision
Short answer questions: 1 to 10
Day 17
Chapter 7 Revision
Try some past JEE questions
Day 18
Chapter 7 Revision
Try some past JEE questions
Day 19
Chapter 7 Revision
Try some past JEE questions
Day 20
Chapter 7 Revision
Try some past JEE questions
Concepts covered
7.1 Angular variables
Angular position
angular velocity
Angular acceleration
Linear speed
Rate of change of speed
Tangential accelaration
7.2 Unit vectors along the radius and the tangent
radial unit vector
Tangential unit vector
7.3 Acceleration in circular motion
Uniform circular motion
Centripetal acceleration
radial component of acceleration
Tangential component of acceleration
7.4 Dynamics of circular motion
Centripetal force
7.5 Circular turnings and banking of roads
When vehicles go through turnings, they travel along a nearly circular arc. That means there is centrepetal accelaration. What forces cause this acceleration? Friction fs can act towards the centre. However this may not be sufficient and the vehicle may skid.
To take care of it, the roads are banked t the turn so that outer part of the road is somewhat lifted up as compared to the inner part. therefore the normal force makes an angle θ wit hte vertical. The horizontal component of the normal force helps in providing the accelaration required.
The θ required for a speed of the vehicle of v is given by
tanθ = v²/rg
7.6 Centrifugal force
What psuedo force is required if the frame of reference rotates at a constant angular velocity ω with respect to an inertial frame?
Cetrifugal force
Coriolis force
Note: It is a common minsconception among the beginners that centrifugal force acts on a particle because the particle goes on a circle. Centrigual force acts (or is assumed to act) becasue we describe the particle from a rotating frame which is noninertial and still use Newton's laws.
7.7 Effect of earth's rotation on apprarent weight
A plumb line stays in a direction which is different from true vertical to earth at that point. The walls of building are built by making them parallel to the plumb line and not to the true vertical.
The weight of a body is mg' and not mg and g' is less than g.
g' = g only at the poles as the poles themselved do not rotate and hence the effect of earth's rotation is not felt there.
---------
JEE Question 2007 Paper I
Two discs A and B are mounted coaxially on a vertical axle. The discs have moments of inertia I and 2I respectively about the common axis. Disc A is imparted an initial angular velocity 2w using the entire potential energy of a spring compressed by a distance x-1 . Disc B is imparted an angular velocity by a spring having the same spring constant and compressed by a distance x-2 . Both the discs rotate in the
clockwise direction
1. The ratio x-1 /x-2 is
(A) 2
(B)1/2
(C) SQRT(2)
(D)1/SQRT(2)
Answer C
2. When disc B is brought in contact with disc A, they acquire a common angular velocity in time t.The average frictional torque on one disc by the other during this period is
3.The loss of kinetic energy during the above process is
--------------------------
JEE question 2007 Paper II
A small object of uniform density rolls up a curved surface with an initial velocity v. It reaches up to a maximum height of 3v^2/4g with respect to the initial position. The object is
(A) ring
(B) solid sphere
(C) hollow sphere
(D) Disc
Answer: D
-------------------------------
JEE Question Paper II 2007
Statement - 1
If there is no external torque on a body about its center of mass, then the velocity of the center of mass remains constant.
Because
Statement - 2
The linear momentum of an isolated system remains constant.
(A) Statement – 1 is True, Statement – 2 is True; Statement – 2 is a correct explanation for statement – 1
(B) Statement – 1 is True, Statement – 2 is True; Statement – 2 is Not a correct explanation for Statement – 1.
(C) Statement – 1 is True, Statement – 2 is False
(D) Statement – 1 is False, Statement – 2 is True
Right choice; D
S1 is incorrect. without external torque but with external force the centre can move.
S2 is correct.
----------------------
JEE 2006
A solid sphere of mass M, radius R and having moment of inertia about an axis passing through the centre of mass as I, is recast into a disc of thickness t, whose moment of inertia about an axis passing through its edge and perpendicular to its plane remains I. Then, radius of the disc will be
(A) 2R/SQRT(15)
(B) R*(SQRT(2/15)
(C) 4R/SQRT(15)
(D) R/4
Answer: A
-------------------------
Uniform Circular motion;
-----------
Sections of the chapter
7.1 Angular variables
7.2 Unit vectors along the radius and the tangent
7.3 Acceleration in circular motion
7.4 Dynamics of circular motion
7.5 Circular turnings and banking of roads
7.6 Centrifugal force
7.7 Effect of earth's rotation on apprarent weight
------------
Study Plan
Day 1
7.1 Angular variables
Ex. 7.1, 7.2
7.2 Unit vectors along the radius and the tangent
Day 2
7.3 Acceleration in circular motion
Ex. 7.3,7.4
7.4 Dynamics of circular motion
Ex. 7.5
W.O.E. 3,4,5,7
Day 3
7.5 Circular turnings and banking of roads
Ex. 7.6
W.O.E. 1 and 2
Day 4
7.6 Centrifugal force
w.O.E. 7, 8,9,10,
Day 5
7.7 Effect of earth's rotation on apprarent weight
Ex. 7.7
w.O.E. 11 to 13
Day 6
Chapter 7
Objective I
Day 7
Chapter 7
Objective II
Day 8
Chapter 7
Exercises 1 to 5
Day 9
Chapter 7
Exercises 6 to 10
Day 10
Chapter 7
Exercises 11 to 15
Revision period
Chapter 7 Revision
Day 11
Chapter 7 Revision
Exercises: 16 to 18
Day 12
Chapter 7 Revision
Exercises: 19 to 21
Day 13
Chapter 7 Revision
Exercises: 22 to 24
Day 14
Chapter 7 Revision
Exercises: 25 to 27
Day 15
Chapter 7 Revision
Exercises: 28 to 30
Day 16
Chapter 7 Revision
Short answer questions: 1 to 10
Day 17
Chapter 7 Revision
Try some past JEE questions
Day 18
Chapter 7 Revision
Try some past JEE questions
Day 19
Chapter 7 Revision
Try some past JEE questions
Day 20
Chapter 7 Revision
Try some past JEE questions
Concepts covered
7.1 Angular variables
Angular position
angular velocity
Angular acceleration
Linear speed
Rate of change of speed
Tangential accelaration
7.2 Unit vectors along the radius and the tangent
radial unit vector
Tangential unit vector
7.3 Acceleration in circular motion
Uniform circular motion
Centripetal acceleration
radial component of acceleration
Tangential component of acceleration
7.4 Dynamics of circular motion
Centripetal force
7.5 Circular turnings and banking of roads
When vehicles go through turnings, they travel along a nearly circular arc. That means there is centrepetal accelaration. What forces cause this acceleration? Friction fs can act towards the centre. However this may not be sufficient and the vehicle may skid.
To take care of it, the roads are banked t the turn so that outer part of the road is somewhat lifted up as compared to the inner part. therefore the normal force makes an angle θ wit hte vertical. The horizontal component of the normal force helps in providing the accelaration required.
The θ required for a speed of the vehicle of v is given by
tanθ = v²/rg
7.6 Centrifugal force
What psuedo force is required if the frame of reference rotates at a constant angular velocity ω with respect to an inertial frame?
Cetrifugal force
Coriolis force
Note: It is a common minsconception among the beginners that centrifugal force acts on a particle because the particle goes on a circle. Centrigual force acts (or is assumed to act) becasue we describe the particle from a rotating frame which is noninertial and still use Newton's laws.
7.7 Effect of earth's rotation on apprarent weight
A plumb line stays in a direction which is different from true vertical to earth at that point. The walls of building are built by making them parallel to the plumb line and not to the true vertical.
The weight of a body is mg' and not mg and g' is less than g.
g' = g only at the poles as the poles themselved do not rotate and hence the effect of earth's rotation is not felt there.
---------
JEE Question 2007 Paper I
Two discs A and B are mounted coaxially on a vertical axle. The discs have moments of inertia I and 2I respectively about the common axis. Disc A is imparted an initial angular velocity 2w using the entire potential energy of a spring compressed by a distance x-1 . Disc B is imparted an angular velocity by a spring having the same spring constant and compressed by a distance x-2 . Both the discs rotate in the
clockwise direction
1. The ratio x-1 /x-2 is
(A) 2
(B)1/2
(C) SQRT(2)
(D)1/SQRT(2)
Answer C
2. When disc B is brought in contact with disc A, they acquire a common angular velocity in time t.The average frictional torque on one disc by the other during this period is
3.The loss of kinetic energy during the above process is
--------------------------
JEE question 2007 Paper II
A small object of uniform density rolls up a curved surface with an initial velocity v. It reaches up to a maximum height of 3v^2/4g with respect to the initial position. The object is
(A) ring
(B) solid sphere
(C) hollow sphere
(D) Disc
Answer: D
-------------------------------
JEE Question Paper II 2007
Statement - 1
If there is no external torque on a body about its center of mass, then the velocity of the center of mass remains constant.
Because
Statement - 2
The linear momentum of an isolated system remains constant.
(A) Statement – 1 is True, Statement – 2 is True; Statement – 2 is a correct explanation for statement – 1
(B) Statement – 1 is True, Statement – 2 is True; Statement – 2 is Not a correct explanation for Statement – 1.
(C) Statement – 1 is True, Statement – 2 is False
(D) Statement – 1 is False, Statement – 2 is True
Right choice; D
S1 is incorrect. without external torque but with external force the centre can move.
S2 is correct.
----------------------
JEE 2006
A solid sphere of mass M, radius R and having moment of inertia about an axis passing through the centre of mass as I, is recast into a disc of thickness t, whose moment of inertia about an axis passing through its edge and perpendicular to its plane remains I. Then, radius of the disc will be
(A) 2R/SQRT(15)
(B) R*(SQRT(2/15)
(C) 4R/SQRT(15)
(D) R/4
Answer: A
-------------------------
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