Study guide H C Verma JEE Physics Ch. 18 GEOMETRICAL OPTICS

JEE syllabus

Optics: Rectilinear propagation of light; Reflection and refraction at plane and spherical surfaces; Total internal reflection; Deviation and dispersion of light by a prism; Thin lenses; Combinations of mirrors and thin lenses; Magnification.

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1. Reflection at smooth surfaces
5. Refraction at plane surfaces
6. Critical angle
8. Prism
9. Refraction at spherical surfaces;
10. refraction through thin lenses

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Sections in Chapter 18 of HV Verma - Geometrical Optics

18.1 reflection at smooth surfaces
18.2 Spherical mirrors
18.3 Relation between u,v and R for spherical mirrors
18.4 extended objects and magnification
18.5 Refraction at plane surfaces
18.6 Critical angle
18.7 Optical fibre
18.8 Prism
18.9 Refraction at spherical surfaces
18.10 extended objects - laterial magnification
18.11 Refraction through thin lenses
18.12 Lens maker's formula and lens formula
18.13 Extended objects: Lateral magninification
18.14 Power of a lens
18.15 thin lenses in contact
18.16 two thin lenses separated by a distance
18.17 defects of images


Study Plan

Day 1

18.1 Reflection at smooth surfaces
18.2 Spherical mirrors
18.3 Relation between u,v and R for spherical mirrors

Example 18.1

Day 2

18.4 extended objects and magnification
18.5 Refraction at plane surfaces
18.6 Critical angle

Examples 18. 2,18.3, 18.4


Day 3

18.7 Optical fibre
18.8 Prism
18.9 Refraction at spherical surfaces

Examples 18.5 to 8
Exercises
1-5

Day 4

18.10 extended objects - laterial magnification
18.11 Refraction through thin lenses

Examples 18.9 to 12
Exercises
6-10


Day 5

18.12 Lens maker's formula and lens formula
18.13 Extended objects: Lateral magninification
18.14 Power of a lens

Examples 18.13 to 16
Exercises
11-15

Day 5

18.15 thin lenses in contact
18.16 two thin lenses separated by a distance
18.17 defects of images

Examples 18.17 to 20
Exercises
16-20

Day 6

Examples 18.17 to 28
Exercises 16-25



Day 7


Exercises 26-45

Day 8
Exercises
46-55


Day 9

Exercises 56 to 65


Day 10

Exercises 66 to 70

Day 11
Exercises 71 to 75

Day 12
Exercises 76 to 79

Day 13
Objective I 1 to 18

Day 14
Objective II 1 to 7

Day 15
Questions for short answer 1 to 19





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Audiovisual lectures

Lesson 48: Reflection and Refraction
www.curriki.org/nroc/Introductory_Physics_2/lesson48/Container.html

Lesson 49: Mirrorswww.curriki.org/nroc/Introductory_Physics_2/lesson49/Container.html

Lesson 50: Lenses
www.curriki.org/nroc/Introductory_Physics_2/lesson50/Container.html






JEE Question 2007 Paper I

In an experiment to determine the focal length (f) of a concave mirror by the u–v method, a student places the object pin A on the principal axis at a distance x from the pole P. The student looks at the pin and its inverted image from a distance keeping his/her eye in line with PA. When the student shifts his/her eye towards left, the image appears to the right of the object pin. Then,

(A) x < f (B) f < x < 2f (C) x = 2f (D) x > 2f

Sol: Ans [B]

Image is between object and eye. So object is within focus of mirror.
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JEE Question 2007 Paper I

STATEMENT-1

The formula connecting u, v and f for a spherical mirror is valid only for mirrors whose sizes are very small compared to their radii of curvature.

because

STATEMENT-2

Laws of reflection are strictly valid for plane surfaces, but not for large spherical surfaces

(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1
(C) Statement-1 is True, Statement-2 is False
(D) Statement-1 is False, Statement-2 is True

Correct choice: C

Laws of reflection are valid for any kind of reflecting surface.
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JEE 2006

A point object is placed at a distance of 20 cm from a thin plano-convex lens of focal length 15 cm. If the plane surface is silvered, the image will form at

(A) 60 cm left of AB (B) 30 cm left of AB
(C) 12 cm left of AB (D) 60 cm right of AB

Answer: C

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JEE 2006

A biconvex lens of focal length f forms a circular image of sun of radius r in focal plane. Then
(A) πr² α f
(B) πr² α f²
(C) if lower half part is covered by black sheet, then area of the image is equal to πr²/2
(D) if f is doubled, intensity will increase

Answer: B
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Updated 1 May 2016,  23 Oct 2007