## Tuesday, October 23, 2007

### Study Guide H C Verma JEE Physics Ch.46 THE NUCLEUS

JEE SYLLABUS

Atomic nucleus; Alpha, beta and gamma radiations; Law of radioactive decay; Decay constant; Half-life and mean life; Binding energy and its calculation; Fission and fusion processes; Energy calculation in these processes.
--------------------
Sections of the chapter

46.1 Properties of a nucleus;
46.2 Nuclear forces
46.3 Binding energy
46.5 Law of radioactive decay; Decay constant; Half-life and mean life;
46.6 Properties and uses of nuclear radiation
46.7 Binding energy and its calculation;
46.8 Fission
46.9 Uranium fission reactor
46.10 Nuclear Fusion
---------------------------
Study Plan

Day 1

46.1 Properties of a nucleus;
46.2 Nuclear forces
46.3 Binding energy

Day 2
Worked out examples 1 to 5

46.5 Law of radioactive decay; Decay constant; Half-life and mean life;

Day 3
46.6 Properties and uses of nuclear radiation
46.7 Energy from the nucleus
Exercises 1 to 5

Day 4

46.8 Fission
46.9 Uranium fission reactor
WOE 6 to 10

Day 5
46.10 Nuclear Fusion
WOE 11 to 15

Day 6
Exercises 6 to 15

Day 7
Exercises 16 to 25

Day 8
Exercises 26 to 35

Day 9
Exercises 36 to 45

Day 10
Exercises 46 to 53

Day 11
Objective I

Day 12
Objective II

Day 13
Concept Review

Day 14
Formula review

---------------------------

For some additional practice questions on the chapter
see
http://iit-jee-physics-ps.blogspot.com/2007/10/simple-questions-ch-46-nucleus.html

-----------------
Audiovisual lectures
Lesson 54: Nuclear Reactions
www.curriki.org/nroc/Introductory_Physics_2/lesson54/Container.html

Lesson 55: Mass-Energy Equivalence
www.curriki.org/nroc/Introductory_Physics_2/lesson55/Container.html

-----------------------
JEE Question 2007 paper I

In the options given below, let E(A,B)X denote the rest mass energy of a nucleus of material X and E(n)of a neutron. The correct option is
(A)E(236,92)U > E(137,53)I + E(97,39)Y + 2E(n)
(B)E(236,92)U < E(137,53)I + E(97,39)Y + 2E(n)
(C)E(236,92)U < E(140,56)Ba + E(94,36)Kr + 2E(n)
(D)E(236,92)U = E(140,56)Ba + E(94,36)Kr + 2E(n)

Sol: Ans [A]
(236,92)U breaks into smaller atoms and gives out energy.
---------------------------