I started my serious relearning effort in May 2007. The first post that I made in this blog was on 16th May 2007. I started the post with a prayer to Ganesha, and the project has progressed till now.
Now I can feel happy that I studied the JEE syllabus more or less fully and I am in a position to explain the various lessons to my child if she needs my help apart from her lectures at the Junior college and further lectures at IIT coaching class.
I started posting some points in the blogs to confirm to myself that I really studied various chapters. Fortunately, these notes are found to be useful by many others, judging by the visits to the blogs.
I presently started model problems blogs for each subject so that I go through some problems in each subject. While these blogs may not be comprehensive at this point of time, because I am not writing them with that objective, substantial amount of material is put into these blogs. I can definitely improve them to provide a more comprehensive material may be after July 2009.
IIT JEE Chemistry Notes
www.iit-jee-chemistry.blogspot.com
IIT JEE Mathematics Notes
www.iit-jee-maths.blogspot.com
COMPANION SITES: www.iit-jee-chemistry.blogspot.com, www.iit-jee-maths.blogspot.com. A google search facility is available at the bottom of the page for searching any topic on these sites.
Thursday, June 26, 2008
Saturday, May 24, 2008
Intensive Study Diary
Time has come for intensive study. May be at the rate of one chapter each week. It means solving lots of problems.
Week ending 25 May 2008 - Mathematics and Physics - Vector algebra and Calculus
Week ending 25 May 2008 - Mathematics and Physics - Vector algebra and Calculus
Tuesday, May 13, 2008
IIT JEE Physics Useful books - Download
Elementary Mechanics and Thermodynamics by John Norburyhttp://www.scribd.com/doc/90229/Elementary-mechanics-and-thermodynamics
Solutions manual
http://www.scribd.com/doc/90222/Solutions-manual-for-mechanics-and-thermodynamics
Quantum Theory - a Very short Introduction by John Polkinghornehttp://www.scribd.com/doc/2676192/Quantum-Theory
Read Albret Einstein's note on Relativity for people with Matriculate Physics Knowledge
http://www.scribd.com/doc/3408/ebook-PDF-Science-Albert-Einstein-Relativity
History of Physics
http://www.scribd.com/doc/322968/A-History-of-Physics-in-Its-Elementary-Branches
Solutions manual
http://www.scribd.com/doc/90222/Solutions-manual-for-mechanics-and-thermodynamics
Quantum Theory - a Very short Introduction by John Polkinghornehttp://www.scribd.com/doc/2676192/Quantum-Theory
Read Albret Einstein's note on Relativity for people with Matriculate Physics Knowledge
http://www.scribd.com/doc/3408/ebook-PDF-Science-Albert-Einstein-Relativity
History of Physics
http://www.scribd.com/doc/322968/A-History-of-Physics-in-Its-Elementary-Branches
Monday, May 12, 2008
Past JEE Objective Questions on Magnetism
Objective questions on magnetism, from the past JEE papers of 1982-88 are posted in
http://iit-jee-physics-ps.blogspot.com/2008/05/past-jee-objective-questions-magnetism.html
http://iit-jee-physics-ps.blogspot.com/2008/05/past-jee-objective-questions-magnetism.html
Thursday, May 8, 2008
IIT JEE Physics Concept Review - An-Az
Angular momentum
(from Rotational Mechanics chapter)
Angular momentum of a particle about a point O is defined as
l = r×p
l, r, and p are vectors.
l = angular momentum of a particle
r = positition vector of the particle from O
p = linear momentum of the particle
Angular momentum of a particle about a line say AB is the component of angular momentum about a point O on the line AB along the line AB. It means to find angular momentum of a particle about a line AB, we have to first find angular momentum about a point O on AB and then find its component along the line AB.
(from Rotational Mechanics chapter)
Angular momentum of a particle about a point O is defined as
l = r×p
l, r, and p are vectors.
l = angular momentum of a particle
r = positition vector of the particle from O
p = linear momentum of the particle
Angular momentum of a particle about a line say AB is the component of angular momentum about a point O on the line AB along the line AB. It means to find angular momentum of a particle about a line AB, we have to first find angular momentum about a point O on AB and then find its component along the line AB.
IIT JEE Physics Concept Review - Ca-Cm
Centrifugal Force:
Newton's laws are not valid if one is working from a noninertial frame. If the frame of reference rotates at a constant angular velocity ω with respect to an inertial frame, we use the pseudo force centrifugal force.
Centrifugal force is assumed act because we describe the particle from a rotating frame which is noninertial and still use Newton's laws.
Example: An observer sitting in a rotating cabin observed that a box is at rest. If the box is at rest, the resultant force on the box has to be zero. The forces on the box are, its weight and the normal contact force between the cabin floor and the box, and the friction force beween the cabin floor and the box. The friction force f = mω²r acts on the box towards the origin. As the weight and the normal contact force cancel each other, to make the resultant zero, a pseudo force with magnitude mω²r is to be assumed which acts on the box away from the centre. This is centrifugal force.
Newton's laws are not valid if one is working from a noninertial frame. If the frame of reference rotates at a constant angular velocity ω with respect to an inertial frame, we use the pseudo force centrifugal force.
Centrifugal force is assumed act because we describe the particle from a rotating frame which is noninertial and still use Newton's laws.
Example: An observer sitting in a rotating cabin observed that a box is at rest. If the box is at rest, the resultant force on the box has to be zero. The forces on the box are, its weight and the normal contact force between the cabin floor and the box, and the friction force beween the cabin floor and the box. The friction force f = mω²r acts on the box towards the origin. As the weight and the normal contact force cancel each other, to make the resultant zero, a pseudo force with magnitude mω²r is to be assumed which acts on the box away from the centre. This is centrifugal force.
IIT JEE Physics Concept Review - Fa-Fm
Flux of an electric field
If in a plane surface area of ∆s, a uniform electric field E exists, and makes an angle θ with the normal to the surface area (positive normal - you can arbitrarily decide which direction is positive), the quantity
∆Φ = E ∆s cos θ
is called the flux of the electric field through the chosen surface.
If ∆s is represented as a vector
∆Φ = E.∆s
Where E and ∆s are vectors and ∆Φ is a scalar quantity.
(Chapter: Gauss's Law)
If in a plane surface area of ∆s, a uniform electric field E exists, and makes an angle θ with the normal to the surface area (positive normal - you can arbitrarily decide which direction is positive), the quantity
∆Φ = E ∆s cos θ
is called the flux of the electric field through the chosen surface.
If ∆s is represented as a vector
∆Φ = E.∆s
Where E and ∆s are vectors and ∆Φ is a scalar quantity.
(Chapter: Gauss's Law)
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